Find all solutions of the given equation in the interval [0, 2$\pi$).
$\frac { 1 } { 2 } \sin 2 x = \cos x$
A) $x = \frac { \pi } { 2 } , \frac { 3 \pi } { 2 }$
B) $x = 0 , \frac { \pi } { 2 } , \pi$
C) $x = 0 , \pi , \frac { \pi } { 2 } , \frac { 3 \pi } { 4 }$
D) $x = 0 , \pi$
E) x = 0

Question

Find all solutions of the given equation in the interval [0, 2$\pi$).  
  $\frac { 1 } { 2 } \sin 2 x = \cos x$  
A) $x = \frac { \pi } { 2 } , \frac { 3 \pi } { 2 }$
B)  $x = 0 , \frac { \pi } { 2 } , \pi$
C)  $x = 0 , \pi , \frac { \pi } { 2 } , \frac { 3 \pi } { 4 }$
D)   $x = 0 , \pi$
E) x = 0

Quizplus · Accepted Answer

The Answer of Find all solutions of the given equation in the interval [0, 2$\pi$).  
  $\frac { 1 } { 2 } \sin 2 x = \cos x$  
A) $x = \frac { \pi } { 2 } , \frac { 3 \pi } { 2 }$
B)  $x = 0 , \frac { \pi } { 2 } , \pi$
C)  $x = 0 , \pi , \frac { \pi } { 2 } , \frac { 3 \pi } { 4 }$
D)   $x = 0 , \pi$
E) x = 0

Find All Solutions of the Given Equation in the Interval π\piπ

Find All Solutions of the Given Equation in the Interval $\pi$