Find the point $( x , y )$ on the unit circle that corresponds to the real number $t = - \frac { \pi } { 6 }$ .Use your results to evaluate cos t.
A)cos t = 1
B)cos t = -1
C) $\cos t = - \frac { \sqrt { 3 } } { 2 }$
D) $\cos t = \frac { \sqrt { 3 } } { 2 }$
E) $\cos t = \frac { 1 } { 2 }$

Question

Find the point $( x , y )$ on the unit circle that corresponds to the real number $t = - \frac { \pi } { 6 }$ .Use your results to evaluate cos t.  
A)cos t = 1
B)cos t = -1
C) $\cos t = - \frac { \sqrt { 3 } } { 2 }$
D) $\cos t = \frac { \sqrt { 3 } } { 2 }$
E) $\cos t = \frac { 1 } { 2 }$

Quizplus · Accepted Answer

The point on the unit circle corresponding to $t = -\frac{\pi}{6}$ has coordinates $\left(\cos\left(-\frac{\pi}{6}\right), \sin\left(-\frac{\pi}{6}\right)\right)$. Since $\cos\left(-\theta\right) = \cos\theta$ and $\sin\left(-\theta\right) = -\sin\theta$, we have $\cos\left(-\frac{\pi}{6}\right) = \cos\left(\frac{\pi}{6}\right) = \frac{\sqrt{3}}{2}$.

Find the Point (x,y)( x , y )(x,y) On the Unit Circle That Corresponds to the Real Number

Find the Point $( x , y )$ On the Unit Circle That Corresponds to the Real Number