Given the equation below, determine two solutions such that
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Question

Given the equation below, determine two solutions such that
 $0 < \theta < 2 \pi$ . sec$\theta$ = $\frac { 2 \sqrt { 3 } } { 3 }$  
A) $\theta = \frac { \pi } { 6 }$
B) $\theta = \frac { 11 \pi } { 8 } , \frac { 7 \pi } { 8 }$
C) $\theta = \frac { 2 \pi } { 4 } , \frac { 5 \pi } { 8 }$
D)  $\theta = \frac { 2 \pi } { 3 } , \frac { \pi } { 3 }$
E) $\theta = \frac { 11 \pi } { 6 } , \frac { \pi } { 6 }$

Quizplus · Accepted Answer

The secant function is the reciprocal of the cosine function. Therefore, sec$\theta$ = $\frac{2\sqrt{3}}{3}$ implies cos$\theta$ = $\frac{\sqrt{3}}{2}$. The angles $\theta = \frac{\pi}{6}$ and $\theta = \frac{11\pi}{6}$ satisfy this condition within the interval $0 < \theta < 2\pi$.

Given the Equation Below, Determine Two Solutions Such That 0<θ<2π0 < \theta < 2 \pi0<θ<2π

Given the Equation Below, Determine Two Solutions Such That $0 < \theta < 2 \pi$