When tuning a piano, a technician strikes a tuning fork for the A above middle C and sets up a wave motion that can be approximated by
Y = 0.001 sin 850 $\pi$t,

Where t is the time (in seconds).

The frequency is given by f = 1 / p.What is the frequency of the note?

A)85 cycles/sec
B) $\frac { 1 } { 425 }$ cycles/sec
C) $\frac { 1 } { 850 }$ cycles/sec
D)850 cycles/sec
E)425 cycles/sec

Question

When tuning a piano, a technician strikes a tuning fork for the A above middle C and sets up a wave motion that can be approximated by  
Y = 0.001 sin 850 $\pi$t,
 
Where t is the time (in seconds).
 
The frequency is given by f = 1 / p.What is the frequency of the note?
 
A)85 cycles/sec
B) $\frac { 1 } { 425 }$ cycles/sec
C) $\frac { 1 } { 850 }$ cycles/sec
D)850 cycles/sec
E)425 cycles/sec

Quizplus · Accepted Answer

The wave function is Y = 0.001 sin 850πt, which is in the form Y = A sin(2πft). Here, 2πf = 850π, so f = 850/2 = 425 cycles/sec.

When Tuning a Piano, a Technician Strikes a Tuning Fork π\piπ

When Tuning a Piano, a Technician Strikes a Tuning Fork $\pi$