For the simple harmonic motion described by the trigonometric function, find the frequency per second. $d = \frac { 1 } { 16 } \cos 12 \pi t$
A)16
B)$\pi$
C)12
D)2$\pi$
E)6

Question

For the simple harmonic motion described by the trigonometric function, find the frequency per second.   $d = \frac { 1 } { 16 } \cos 12 \pi t$  
A)16 
B)$\pi$
C)12
D)2$\pi$
E)6

Quizplus · Accepted Answer

The function is in the form $d = A \cos(2\pi ft)$, where $f$ is the frequency. Here, the angular frequency $\omega = 12\pi$, so $2\pi f = 12\pi$. Solving for $f$, we get $f = 6$.

For the Simple Harmonic Motion Described by the Trigonometric Function d=116cos⁡12πtd = \frac { 1 } { 16 } \cos 12 \pi td=161​cos12πt

For the Simple Harmonic Motion Described by the Trigonometric Function $d = \frac { 1 } { 16 } \cos 12 \pi t$