For the simple harmonic motion described by the trigonometric function, find the least positive value of t for which
$d = 0$ $d = 6 \cos \frac { 6 \pi } { 5 } t$
A) $\frac { 12 } { 5 }$
B) $\frac { 5 } { 12 }$
C) $\frac { 5 } { 6 }$
D) $\frac { 6 } { 5 }$
E) $\frac { 1 } { 6 }$

Question

For the simple harmonic motion described by the trigonometric function, find the least positive value of t for which 
$d = 0$   $d = 6 \cos \frac { 6 \pi } { 5 } t$ 
A) $\frac { 12 } { 5 }$
B) $\frac { 5 } { 12 }$
C) $\frac { 5 } { 6 }$
D) $\frac { 6 } { 5 }$
E) $\frac { 1 } { 6 }$

Quizplus · Accepted Answer

To find the least positive value of $t$ for which $d = 0$, we set the equation $d = 6 \cos \frac { 6 \pi } { 5 } t = 0$ and solve for $t$. The cosine function equals zero at $\frac{\pi}{2}$ and every odd multiple of $\frac{\pi}{2}$. Thus, we set $\frac { 6 \pi } { 5 } t = \frac{\pi}{2}$ and solve for $t$, giving $t = \frac { 5 } { 12 }$.

For the Simple Harmonic Motion Described by the Trigonometric Function d=0d = 0d=0

For the Simple Harmonic Motion Described by the Trigonometric Function $d = 0$