Evaluate $g ( x ) = \ln x$ at the indicated value of x. $x = e ^ { - 9 }$
A)9
B) $- \frac { 1 } { 9 }$
C)-9
D) $\frac { 1 } { 9 }$
E) $e ^ { - 9 }$

Question

Evaluate $g ( x ) = \ln x$ at the indicated value of x.  $x = e ^ { - 9 }$ 
A)9
B) $- \frac { 1 } { 9 }$
C)-9
D) $\frac { 1 } { 9 }$
E) $e ^ { - 9 }$

Quizplus · Accepted Answer

The natural logarithm function, denoted as $\ln$, is the inverse of the exponential function $e^x$. Therefore, $\ln(e^x) = x$. Given $x = e^{-9}$, evaluating $g(x) = \ln(x)$ at this value gives $g(e^{-9}) = \ln(e^{-9}) = -9$.

Evaluate g(x)=ln⁡xg ( x ) = \ln xg(x)=lnx At the Indicated Value of X

Evaluate $g ( x ) = \ln x$ At the Indicated Value of X