Solve the exponential equation algebraically.Approximate the result to three decimal places. $e ^ { x } - 6 = 13$
A) $\ln 19 \approx - 2.565$
B) $\ln 19 \approx 2.944$
C) $\ln 19 \approx 1.792$
D) $\ln 19 \approx 2.565$
E) $\ln 19 \approx - 2.944$

Question

Solve the exponential equation algebraically.Approximate the result to three decimal places.   $e ^ { x } - 6 = 13$  
A) $\ln 19 \approx - 2.565$
B) $\ln 19 \approx 2.944$
C) $\ln 19 \approx 1.792$
D) $\ln 19 \approx 2.565$
E) $\ln 19 \approx - 2.944$

Quizplus · Accepted Answer

First, solve the equation for x: $e^x - 6 = 13$ leads to $e^x = 19$. Taking the natural logarithm of both sides gives $x = \ln 19$. The approximate value of $\ln 19$ is 2.944.

Solve the Exponential Equation Algebraically ex−6=13e ^ { x } - 6 = 13ex−6=13

Solve the Exponential Equation Algebraically $e ^ { x } - 6 = 13$