Find all the real zeros of the polynomial function. $f ( x ) = x ^ { 2 } - 9$
A) $- 9$
B) $3$
C) $- 3$
D) $9$
E) $\pm 3$

Question

Find all the real zeros of the polynomial function.   $f ( x ) = x ^ { 2 } - 9$  
A) $- 9$
B) $3$
C) $- 3$
D) $9$
E) $\pm 3$

Quizplus · Accepted Answer

The zeros of a polynomial are the values of $x$ for which $f(x) = 0$. To find the zeros of $f(x) = x^2 - 9$, we set $f(x) = 0$ and solve for $x$:$$x^2 - 9 = 0$$$$(x - 3)(x + 3) = 0$$$$x - 3 = 0 \quad \text{or} \quad x + 3 = 0$$$$x = 3 \quad \text{or} \quad x = -3$$Therefore, the real zeros of $f(x) = x^2 - 9$ are $x = \pm 3$.

Find All the Real Zeros of the Polynomial Function f(x)=x2−9f ( x ) = x ^ { 2 } - 9f(x)=x2−9

Find All the Real Zeros of the Polynomial Function $f ( x ) = x ^ { 2 } - 9$