Solve the equation and write complex solutions in standard form.
$x ^ { 2 } + 10 x + 29 = 0$

A) $x = 10 - 2 i , 10 + 2 i$
B) $x = - 2 - 5 i , - 2 + 5 i$
C) $x = - 5 + 4 i , - 5 - 4 i$
D) $x = - 5 - 2 i , - 5 + 2 i$
E) $x = - 2 + 25 i , - 2 - 25 i$

Question

Solve the equation and write complex solutions in standard form. 
 $x ^ { 2 } + 10 x + 29 = 0$

A) $x = 10 - 2 i , 10 + 2 i$
B)  $x = - 2 - 5 i , - 2 + 5 i$
C)  $x = - 5 + 4 i , - 5 - 4 i$
D)  $x = - 5 - 2 i , - 5 + 2 i$
E)  $x = - 2 + 25 i , - 2 - 25 i$

Quizplus · Accepted Answer

Using the quadratic formula, $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ with $a = 1$, $b = 10$, and $c = 29$, we find the discriminant $b^2 - 4ac = 100 - 116 = -16$. Thus, $x = \frac{-10 \pm \sqrt{-16}}{2} = \frac{-10 \pm 4i}{2} = -5 \pm 2i$.

Solve the Equation and Write Complex Solutions in Standard Form x2+10x+29=0x ^ { 2 } + 10 x + 29 = 0x2+10x+29=0

Solve the Equation and Write Complex Solutions in Standard Form $x ^ { 2 } + 10 x + 29 = 0$