Find the zeros of the rational function. $g ( x ) = \frac { x ^ { 2 } - 9 } { x + 3 }$
A)x = 0
B)x = -9
C)x = 3
D)x = 9
E)x = -3

Question

Find the zeros of the rational function.   $g ( x ) = \frac { x ^ { 2 } - 9 } { x + 3 }$  
A)x = 0
B)x = -9
C)x = 3
D)x = 9
E)x = -3

Quizplus · Accepted Answer

The zeros of the function are found by setting the numerator equal to zero and solving for x. The numerator is $x^2 - 9$, which factors into $(x + 3)(x - 3)$. Setting this equal to zero gives $x = -3$ and $x = 3$. However, $x = -3$ is not a zero of the rational function because it makes the denominator zero, which is undefined. Therefore, the only zero of the function is $x = 3$.

Find the Zeros of the Rational Function g(x)=x2−9x+3g ( x ) = \frac { x ^ { 2 } - 9 } { x + 3 }g(x)=x+3x2−9​

Find the Zeros of the Rational Function $g ( x ) = \frac { x ^ { 2 } - 9 } { x + 3 }$