Find the domain of the function. $g ( p ) = \sqrt { 81 - p ^ { 2 } }$
A)-9$\le$ p $\le$ 9
B)p $\le$ -9 or p $\ge$ 9
C)p $\ge$ 0
D)p $\le$ 9
E)all real numbers

Question

Find the domain of the function. $g ( p ) = \sqrt { 81 - p ^ { 2 } }$
A)-9$\le$  p $\le$  9
B)p $\le$  -9 or p $\ge$ 9
C)p $\ge$ 0
D)p $\le$  9
E)all real numbers

Quizplus · Accepted Answer

The domain of $g(p) = \sqrt{81 - p^2}$ consists of all values of $p$ for which the expression under the square root, $81 - p^2$, is greater than or equal to 0. This inequality can be rewritten as $-9 \leq p \leq 9$, meaning $p$ must be between -9 and 9, inclusive.

Find the Domain of the Function g(p)=81−p2g ( p ) = \sqrt { 81 - p ^ { 2 } }g(p)=81−p2​

Find the Domain of the Function $g ( p ) = \sqrt { 81 - p ^ { 2 } }$