Find all real values of x such that f(x) = 0.
$f ( x ) = \frac { 81 - x ^ { 2 } } { 3 }$
A)x = ±12
B)x = ±13
C)x = ±11
D)x = ±10
E)x = ±9

Name: Find all real values of x such that f(x) = 0. $f ( x ) = \frac { 81 - x ^ { 2 } } { 3 }$ A)x = ±12 B)x = ±13 C)x = ±11 D)x = ±10 E)x = ±9
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Question

Find all real values of x such that f(x) = 0. 
 $f ( x ) = \frac { 81 - x ^ { 2 } } { 3 }$  
A)x = ±12
B)x = ±13
C)x = ±11
D)x = ±10
E)x = ±9

Quizplus · Accepted Answer

To find the values of x for which f(x) = 0, set the function equal to zero: $ \frac{81 - x^2}{3} = 0 $. This implies $ 81 - x^2 = 0 $, which simplifies to $ x^2 = 81 $. Solving for x gives $ x = \pm 9 $.

Find All Real Values of X Such That F(x) = f(x)=81−x23f ( x ) = \frac { 81 - x ^ { 2 } } { 3 }f(x)=381−x2​

Find All Real Values of X Such That F(x) = $f ( x ) = \frac { 81 - x ^ { 2 } } { 3 }$