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An Object Is Thrown Upward from a Height of 6

Question 239

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An object is thrown upward from a height of 6.4 feet at a velocity of 80 feet per second. Use the position equation s = -16t2 + v0t + s0 to select a function that represents the situation and select the graph of the function.
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A) s = -16t2 + 80 - 6.4​ An object is thrown upward from a height of 6.4 feet at a velocity of 80 feet per second. Use the position equation s = -16t<sup>2</sup> + v<sub>0</sub>t + s<sub>0</sub> to select a function that represents the situation and select the graph of the function. ​ A) s = -16t<sup>2</sup> + 80 - 6.4​ B) s = -16t<sup>2</sup> + 80t​​ C) s = -16t<sup>2</sup> - 80t - 6.4​ D) s = -16t<sup>2</sup> - 80t + 6.4​ E) s = -16t<sup>2</sup> + 80t + 6.4​​
B) s = -16t2 + 80t​​ An object is thrown upward from a height of 6.4 feet at a velocity of 80 feet per second. Use the position equation s = -16t<sup>2</sup> + v<sub>0</sub>t + s<sub>0</sub> to select a function that represents the situation and select the graph of the function. ​ A) s = -16t<sup>2</sup> + 80 - 6.4​ B) s = -16t<sup>2</sup> + 80t​​ C) s = -16t<sup>2</sup> - 80t - 6.4​ D) s = -16t<sup>2</sup> - 80t + 6.4​ E) s = -16t<sup>2</sup> + 80t + 6.4​​
C) s = -16t2 - 80t - 6.4​ An object is thrown upward from a height of 6.4 feet at a velocity of 80 feet per second. Use the position equation s = -16t<sup>2</sup> + v<sub>0</sub>t + s<sub>0</sub> to select a function that represents the situation and select the graph of the function. ​ A) s = -16t<sup>2</sup> + 80 - 6.4​ B) s = -16t<sup>2</sup> + 80t​​ C) s = -16t<sup>2</sup> - 80t - 6.4​ D) s = -16t<sup>2</sup> - 80t + 6.4​ E) s = -16t<sup>2</sup> + 80t + 6.4​​
D) s = -16t2 - 80t + 6.4​ An object is thrown upward from a height of 6.4 feet at a velocity of 80 feet per second. Use the position equation s = -16t<sup>2</sup> + v<sub>0</sub>t + s<sub>0</sub> to select a function that represents the situation and select the graph of the function. ​ A) s = -16t<sup>2</sup> + 80 - 6.4​ B) s = -16t<sup>2</sup> + 80t​​ C) s = -16t<sup>2</sup> - 80t - 6.4​ D) s = -16t<sup>2</sup> - 80t + 6.4​ E) s = -16t<sup>2</sup> + 80t + 6.4​​
E) s = -16t2 + 80t + 6.4​​ An object is thrown upward from a height of 6.4 feet at a velocity of 80 feet per second. Use the position equation s = -16t<sup>2</sup> + v<sub>0</sub>t + s<sub>0</sub> to select a function that represents the situation and select the graph of the function. ​ A) s = -16t<sup>2</sup> + 80 - 6.4​ B) s = -16t<sup>2</sup> + 80t​​ C) s = -16t<sup>2</sup> - 80t - 6.4​ D) s = -16t<sup>2</sup> - 80t + 6.4​ E) s = -16t<sup>2</sup> + 80t + 6.4​​

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