Find the zeros of the function algebraically.
$f ( x ) = \frac { x } { 9 x ^ { 2 } - 5 }$
A)x = 5
B)x = 10
C)x = 9
D)x = 8
E)x = 0

Question

Find the zeros of the function algebraically. 
$f ( x ) = \frac { x } { 9 x ^ { 2 } - 5 }$  
A)x = 5
B)x = 10
C)x = 9
D)x = 8
E)x = 0

Quizplus · Accepted Answer

To find the zeros of the function, set $f(x) = 0$ and solve for $x$. This gives $0 = \frac{x}{9x^2 - 5}$. The numerator $x = 0$ is the only value that makes the fraction equal to zero, since the denominator $9x^2 - 5$ cannot be zero (as it would make the fraction undefined). Therefore, the zero of the function is $x = 0$.

Find the Zeros of the Function Algebraically f(x)=x9x2−5f ( x ) = \frac { x } { 9 x ^ { 2 } - 5 }f(x)=9x2−5x​

Find the Zeros of the Function Algebraically $f ( x ) = \frac { x } { 9 x ^ { 2 } - 5 }$