Find ( f / g )(x). $f ( x ) = x ^ { 2 } - 4 x \quad g ( x ) = 7 - x$
A) $( f / g ) ( x ) = \frac { x ^ { 2 } - 4 x } { 7 - x } , x \neq 0$
B) $( f / g ) ( x ) = \frac { x - 4 } { 7 } , x \neq 0$
C) $( f / g ) ( x ) = \frac { x ^ { 2 } } { 7 } + 4 , x \neq 0$
D) $( f / g ) ( x ) = \frac { x ^ { 2 } - 4 x } { 7 - x } , x \neq 7$
E) $( f / g ) ( x ) = \frac { x ^ { 2 } - 4 x } { 7 - x } , x \neq - 7$

Question

Find ( f / g )(x). $f ( x ) = x ^ { 2 } - 4 x \quad g ( x ) = 7 - x$  
A) $( f / g ) ( x ) = \frac { x ^ { 2 } - 4 x } { 7 - x } , x \neq 0$
B) $( f / g ) ( x ) = \frac { x - 4 } { 7 } , x \neq 0$
C) $( f / g ) ( x ) = \frac { x ^ { 2 } } { 7 } + 4 , x \neq 0$
D) $( f / g ) ( x ) = \frac { x ^ { 2 } - 4 x } { 7 - x } , x \neq 7$  
E) $( f / g ) ( x ) = \frac { x ^ { 2 } - 4 x } { 7 - x } , x \neq - 7$

Quizplus · Accepted Answer

The division of $f(x)$ by $g(x)$ is $\frac{x^2 - 4x}{7 - x}$. The restriction comes from the denominator $7 - x$, which cannot be zero, hence $x \neq 7$.

Find ( F / G )(X) f(x)=x2−4xg(x)=7−xf ( x ) = x ^ { 2 } - 4 x \quad g ( x ) = 7 - xf(x)=x2−4xg(x)=7−x

Find ( F / G )(X) $f ( x ) = x ^ { 2 } - 4 x \quad g ( x ) = 7 - x$