Find $g \circ g$ .
$g ( x ) = x - 2$

A) $( x - 2 ) ^ { 2 }$
B) $x ^ { 2 } - 2$
C) $x + 4$
D) $- x - 4$
E) $x - 4$

Name: Find $g \circ g$ . $g ( x ) = x - 2$ A) $( x - 2 ) ^ { 2 }$ B) $x ^ { 2 } - 2$ C) $x + 4$ D) $- x - 4$ E) $x - 4$
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Question

Find $g \circ g$ . 
 $g ( x ) = x - 2$

A) $( x - 2 ) ^ { 2 }$
B) $x ^ { 2 } - 2$
C) $x + 4$
D) $- x - 4$
E) $x - 4$

Quizplus · Accepted Answer

To find $g \circ g$, we substitute $g(x)$ into itself: $g(g(x)) = g(x - 2) = (x - 2) - 2 = x - 4$.

Find g∘gg \circ gg∘g g(x)=x−2g ( x ) = x - 2g(x)=x−2

Find $g \circ g$ $g ( x ) = x - 2$