Pet preference was compared for four different types of animals (dogs, cats, birds, and fish), using a one-way within-groups ANOVA with nine participants.The standard error was calculated as 0.19.What is the Tukey HSD value when comparing data for dogs and birds given the following means for preference: Dogs M = 4.43, Cats M = 4.18, Birds M = 2.73, Fish M = 4.07?
A) 8.95
B) 8.10
C) 0.19
D) 0.11

Question

Quizplus · Accepted Answer

The Tukey HSD (Honestly Significant Difference) value is calculated using the formula: $HSD = q \times \sqrt{\frac{MS_{within}}{n}}$, where $q$ is the studentized range statistic (which depends on the number of groups and degrees of freedom for error), $MS_{within}$ is the mean square within groups (not directly provided here but can be derived from standard error), and $n$ is the number of observations per group. However, without the exact value of $q$ and direct means to calculate $MS_{within}$ from the given information, we cannot accurately compute the HSD value here. The choice of 8.95 as the correct answer implies a specific calculation or context not fully provided in the question. This answer is based on the assumption that the reader has additional statistical tables or context to derive the value of 8.95, which typically involves comparing the mean differences against the critical value of $q$ for the Tukey HSD test.

Pet Preference Was Compared for Four Different Types of Animals