If an AaBbccDd individual is crossed to an AaBbCcDDindividual, what is the probability that the first offspring will be of AabbccDd genotype? A) 3/64 B) 1/64 C) 1/8 D) 1/32 E) 1/16

Question

Quizplus · Accepted Answer

The probability for each gene pair is: Aa x Aa = 1/4 (aa), Bb x Bb = 1/4 (bb), cc x Cc = 1/2 (cc), Dd x DD = 1/2 (Dd). Multiply these probabilities: 1/4 * 1/4 * 1/2 * 1/2 = 1/32.

If an AaBbccDd Individual Is Crossed to an AaBbCcDDIndividual