A ball is thrown upward at a velocity of 19.6 m/s.What is its velocity after 3.0 s,assuming negligible air resistance?
A)9.8 m/s upward
B)9.8 m/s downward
C)0 m/s
D)19.6 m/s downward

Question

Quizplus · Accepted Answer

The velocity of the ball after 3.0 s can be calculated using the equation $v = u + at$, where $v$ is the final velocity, $u$ is the initial velocity (19.6 m/s upward), $a$ is the acceleration due to gravity (-9.8 m/s$^2$ downward), and $t$ is the time (3.0 s). Plugging in the values, we get $v = 19.6 m/s - (9.8 m/s^2 \times 3.0 s) = 19.6 m/s - 29.4 m/s = -9.8 m/s$, indicating a velocity of 9.8 m/s downward.

A Ball Is Thrown Upward at a Velocity of 19