A boy jumps with a velocity of magnitude 20.0 m/s at an angle of 25.0° above the horizontal.What is the horizontal component of the boy's velocity?
A)18.1 m/s
B)15.6 m/s
C)8.45 m/s
D)12.6 m/s
E)9.33 m/s

Question

Quizplus · Accepted Answer

The horizontal component of the velocity can be calculated using the formula $v_x = v \cos(\theta)$, where $v = 20.0 \, \text{m/s}$ is the magnitude of the velocity and $\theta = 25.0°$ is the angle. Calculating gives $v_x = 20.0 \cos(25.0°) \approx 18.1 \, \text{m/s}$.

A Boy Jumps with a Velocity of Magnitude 20