Two 3.0 ?C charges lie on the x-axis, one at the origin and the other at $2.0 \mathrm {~m}$ What is the potential (relative to infinity)due to these charges at a point at $6.0 \mathrm {~m}$ on the x-axis? (k = 1/4??₀ = 9.0 × 10⁹ N ? m²/C²)

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Quizplus · Accepted Answer

The potential at a point due to a point charge is given by $ V = \frac{kQ}{r} $. Calculate the potential due to each charge at 6.0 m and sum them: $ V = \frac{9.0 \times 10^9 \times 3.0 \times 10^{-6}}{6} + \frac{9.0 \times 10^9 \times 3.0 \times 10^{-6}}{4} = 4500 + 6750 = 11250 \approx 11,000 $ V.

Two 30 ?C Charges Lie on the X-Axis, One at the the Origin