A 250-kg crate is on a rough ramp,inclined at 30° above the horizontal.The coefficient of kinetic friction between the crate and ramp is 0.22.A horizontal force of 5000 N is applied to the crate,pushing it up the ramp.What is the acceleration of the crate? A) 8.4 m/s² B) 10 m/s² C) 12 m/s² D) 13 m/s² E) 3.4 m/s²

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Quizplus · Accepted Answer

The force of friction is:$$f_k=\mu_k n=\mu_k mg\cos	heta$$The net force on the crate is:$$F_{net}=F-f_k=ma$$$$a=\frac{F-\mu_k mg\cos	heta}{m}$$$$a=\frac{5000	ext{ N}-(0.22)(250	ext{ kg})(9.8	ext{ m/s}^2)\cos30\degree}{250	ext{ kg}}$$$$a=8.4	ext{ m/s}^2$$

A 250-Kg Crate Is on a Rough Ramp,inclined at 30°