Consider the diagram presented below.Determine the system reliability if the reliabilities of the individual components are: A = 0.92,B = 0.95,C = 0.93,D = 0.99,E = 0.92,F = 0.90,G = 0.97,H = 0.96.
Subsystem reliabilities:
First (A,B,C): 1 - (1 - 0.92)(1 - 0.95)(1 - 0.93)= 0.99972
Second (D): 0.99
Third (E,F,G,H): 1 - [1 - (0.92)(0.90)][1 - (0.97)(0.96)] = 0.9881664
System reliability = (0.99972)(0.99)(0.9881664)= 0.978011
Correct Answer:
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First (A,B,C): ...
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