A nucleus with mass number A and atomic number Z undergoes $\beta$⁺ decay.The mass number and atomic number, respectively, of the daughter nucleus are: A)A - 1, Z - 1 B)A - 1, Z + 1 C)A + 1, Z - 1 D)A, Z + 1 E)A, Z - 1

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The Answer of A nucleus with mass number A and atomic number Z undergoes $\beta$⁺ decay.The mass number and atomic number, respectively, of the daughter nucleus are: A)A - 1, Z - 1 B)A - 1, Z + 1 C)A + 1, Z - 1 D)A, Z + 1 E)A, Z - 1

A Nucleus with Mass Number a and Atomic Number Z β\betaβ

A Nucleus with Mass Number a and Atomic Number Z $\beta$