You have stated your alternative hypothesis as $S \bar{X}_{1}-\bar{X}_{2}$ $H_{a}: \mu_{1}-\mu_{2} \neq 0$ .If $\bar{X}_{1}$ = 23, $\bar{X}_{2}$ = 25, $n_{1}$ = 15, $n_{2}$ = 15, and
= 0.90, what is $t_{o b t}$ ?

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The Answer of You have stated your alternative hypothesis as $S \bar{X}_{1}-\bar{X}_{2}$ $H_{a}: \mu_{1}-\mu_{2} \neq 0$ .If $\bar{X}_{1}$ = 23, $\bar{X}_{2}$ = 25, $n_{1}$ = 15, $n_{2}$ = 15, and
= 0.90, what is $t_{o b t}$ ?

You Have Stated Your Alternative Hypothesis As SXˉ1−Xˉ2S \bar{X}_{1}-\bar{X}_{2}SXˉ1​−Xˉ2​ Ha:μ1−μ2≠0H_{a}: \mu_{1}-\mu_{2} \neq 0Ha​:μ1​−μ2​=0

You Have Stated Your Alternative Hypothesis As $S \bar{X}_{1}-\bar{X}_{2}$ $H_{a}: \mu_{1}-\mu_{2} \neq 0$