A solution of glucose has 10.00 g glucose (molecular weight = 180.g/mol)in 1.00 L of water.How many molecules of glucose are in 1.00 L of the solution? A) 0.05 molecules B) 180 molecules C) 3.34 ×10²² molecules D) 6.02 × 10²³ molecules E) 6.02 × 10²⁴ molecules

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Quizplus · Accepted Answer

First, calculate the moles of glucose: $ \frac{10.00 \, \text{g}}{180.0 \, \text{g/mol}} = 0.0556 \, \text{moles} $. Then, use Avogadro's number ($6.02 \times 10^{23}$ molecules/mol) to find the number of molecules: $0.0556 \, \text{moles} \times 6.02 \times 10^{23} \, \text{molecules/mol} = 3.34 \times 10^{22} \, \text{molecules}$.

A Solution of Glucose Has 10