A technician adds 0.025 L of 200 mM buffer stock solution to a volumetric flask and dilutes the stock to 1.0 L.What is the final concentration of the solution?
A) 0.11 mM
B) 110 mM
C) 11 mM
D) 50 mM
E) 5.0 mM

Question

Quizplus · Accepted Answer

The final concentration is calculated using the dilution formula $C_1V_1 = C_2V_2$, where $C_1$ is the initial concentration (200 mM), $V_1$ is the initial volume (0.025 L), $C_2$ is the final concentration, and $V_2$ is the final volume (1.0 L). Solving for $C_2$ gives $C_2 = \frac{C_1V_1}{V_2} = \frac{200 \times 0.025}{1} = 5.0$ mM.

A Technician Adds 0