Jamal pulls a 150-N sled up a 28.0 $\degree$ slope at constant speed by a force of 120 N. Near the top of the hill he releases the sled. With what acceleration does the sled go down the hill? A) 1.20 m/s² B) 1.36 m/s² C) 2.22 m/s² D) 2.67 m/s²

Question

Quizplus · Accepted Answer

The net force acting on the sled when it goes down the hill is the component of gravitational force along the slope minus the frictional force. The gravitational force component is 150 N * sin(28°), and the frictional force is 120 N. Using Newton's second law, the acceleration is calculated as (150 N * sin(28°) - 120 N) / (150 N / 9.8 m/s²), which gives approximately 1.36 m/s².

Jamal Pulls a 150-N Sled Up a 28 °\degree° Slope at Constant Speed by a Force of 120 N

Jamal Pulls a 150-N Sled Up a 28 $\degree$ Slope at Constant Speed by a Force of 120 N