A force of 200 N is applied to a 50-kg mass in the direction of motion for a distance of 6.0 m, and then the force is increased to 300 N for the next 5.0 m. For the 11 m of travel, how much work is done by the varying force?
A) "2700 J"
B) "1500 J"
C) "2400 J"
D) "-1200 J"

Question

Quizplus · Accepted Answer

The work done is calculated by summing the work done over each segment: W = F1 * d1 + F2 * d2 = 200 N * 6 m + 300 N * 5 m = 1200 J + 1500 J = 2700 J.

A Force of 200 N Is Applied to a 50-Kg