The position of a 0.64-kg mass undergoing simple harmonic motion is given by x = (0.160 m) cos ( $\pi$t/8). What is its period of oscillation?
A) 100 s
B) 32 s
C) 16 s
D) 8.0 s

Question

Quizplus · Accepted Answer

The period of oscillation T is given by the formula T = 2π/ω, where ω is the angular frequency. In the given equation x = (0.160 m) cos (πt/8), the angular frequency ω is π/8. Therefore, T = 2π/(π/8) = 16 s.

The Position of a 0 π\piπ T/8) What Is Its Period of Oscillation? A) 100 S

The Position of a 0 $\pi$ T/8) What Is Its Period of Oscillation?
A) 100 S