How many atoms are present in a sample of pure iron with a mass of 210 g? (The atomic mass of iron = 56 u and N_A = 6.02* 10²³.) A) 1.8 *10¹⁹ B) 2.3 *10²⁸ C) 2.3 *10²⁴ D) 3.2 * 10²⁸

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Quizplus · Accepted Answer

To find the number of atoms, use the formula: (mass of sample / atomic mass) * Avogadro's number. For 210 g of iron: (210 g / 56 g/mol) * 6.02 x 10^23 atoms/mol = 2.3 x 10^24 atoms.

How Many Atoms Are Present in a Sample of Pure