Two parallel wires are separated by 0.25 m. Wire A carries 4.1 A and Wire B carries 10 A, both currents in the same direction. The magnetic permeability in empty space µ₀ = 4 $\pi$ * 10 ^- ⁷ T.m/A. The magnitude of the force on 1.4 m of Wire A is: A) 2.6 * 10^-5 N. B) 4.6 * 10^-5 N. C) less than 1.0 * 10^-5 N. D) 3.2 *10^-5 N.

Question

Quizplus · Accepted Answer

The force per unit length between two parallel currents is given by F/L = (µ₀ * I₁ * I₂) / (2π * d). Substituting the given values, the force on 1.4 m of Wire A is calculated to be approximately 4.6 × 10⁻⁵ N.

Two Parallel Wires Are Separated by 0 π\piπ * 10 - 7 T

Two Parallel Wires Are Separated by 0 $\pi$ * 10 ^- ⁷ T