A proton is released such that it has an initial speed of 5.0 *10⁵ m/s from left to right across the page. A magnetic field of 1.2 T is present at an angle of 30° to the horizontal direction (or positive x axis). What is the magnitude of the force experienced by the proton? (q_p = 1.6 *10^-¹⁹C) A) 3.8 *10^-¹⁴ N B) 7.5 * 10³N C) 4.8 *10^-¹⁴ N D) 1.3 * 10^-¹⁹ N

Question

Quizplus · Accepted Answer

The force on a charged particle moving in a magnetic field is given by F = qvBsinθ. Substituting the given values: F = (1.6 × 10^-19 C)(5.0 × 10^5 m/s)(1.2 T)sin(30°) = 4.8 × 10^-14 N.

A Proton Is Released Such That It Has an Initial