An object is 12.0 cm from the surface of a spherical Christmas tree ornament that is 10.0 cm in diameter. What is the magnification of the image?
A) "-0.500"
B) "-0.200"
C) "+0.172"
D) "+0.143"

Question

Quizplus · Accepted Answer

The magnification of the image is given by the equation:$$m = - \frac{d_i}{d_o}$$where $d_i$ is the image distance and $d_o$ is the object distance.In this case, the object distance is 12.0 cm and the image distance is 10.0 cm. Therefore, the magnification is:$$m = - \frac{10.0 cm}{12.0 cm} = -0.833$$The negative sign indicates that the image is virtual and upright.

An Object Is 12