Neglecting recoil of the gold nucleus, how much kinetic energy must an alpha particle (charge = 2 * 1.6 *10 - 19 C) have to approach to within 1.95 *10 - 14 m of a gold nucleus (charge = 79 * 1.6 * 10 - 19 C) ? (ke = 8.99 *109 N.m2/C2 and 1 MeV = 1.6 *10 - 13 J)
A) 14.6 MeV
B) 11.7 MeV
C) 18.2 MeV
D) 22.7 MeV
Correct Answer:
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