An unopened soda bottle at 25°C contains CO₂ gas at 6.2 atm.Calculate the equilibrium concentration of CO₂ in the unopened soda bottle.[ $\mathrm { K } _ { \mathrm { CO } _ { 2 } }$ = 3.1 × 10^-2mol/(L•atm)] A)0.19 mol/L B)200 mol/L C)0.005 mol/L D)19.2 mol/L E)3.1 mol/L

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Quizplus · Accepted Answer

The equilibrium concentration of CO2 in the soda can be calculated using Henry's law, which states that the solubility of a gas in a liquid at a given temperature is directly proportional to the pressure of the gas above the liquid. The formula for Henry's law is given by: $$C = kP$$ where $C$ is the concentration of the gas in the liquid, $k$ is the Henry's law constant, and $P$ is the partial pressure of the gas. Given that $k = 3.1 \times 10^{-2}$ mol/(L•atm) and $P = 6.2$ atm, the concentration $C$ can be calculated as: $$C = (3.1 \times 10^{-2}) \times 6.2 = 0.1922 \approx 0.19 \text{ mol/L}$$

An Unopened Soda Bottle at 25°C Contains CO2 Gas at 6.2

An Unopened Soda Bottle at 25°C Contains CO₂ Gas at 6.2