Data from a randomized block design are shown in the following table. $\begin{array}{c}
\quad\quad\quad\text { Treatment Levels }\
\begin{array}{l}
\
\text {Block 1}\
\text {Block 2}\
\text {Block3}
\end{array}
\begin{array}{l}
1 \
8 \
6 \
7
\end{array}
\begin{array}{l}
2 \
5 \
6 \
8
\end{array}
\begin{array}{c}
3 \
10 \
9 \
8
\end{array}
\begin{array}{r}
4\
7\
5\
9
\end{array}
\end{array}$

Using$\alpha$ = 0.05, the critical F value for the treatments null hypothesis is ________.
A)3.59
B)4.76
C)3.98
D)5.14
E)9.89

Question

Data from a randomized block design are shown in the following table. $\begin{array}{c}
\quad\quad\quad\text { Treatment Levels }\
\begin{array}{l}
\
\text {Block 1}\
\text {Block 2}\
\text {Block3}
\end{array}
\begin{array}{l}
1 \
8 \
6 \
7 
\end{array}
\begin{array}{l}
2 \
5 \
6 \
8 
\end{array}
\begin{array}{c}
3 \
10 \
9 \
8 
\end{array}
\begin{array}{r}
4\
7\
5\
9
\end{array}
\end{array}$

Using$\alpha$ = 0.05, the critical F value for the treatments null hypothesis is ________.
A)3.59
B)4.76
C)3.98
D)5.14
E)9.89

Quizplus · Accepted Answer

The critical F value is determined by the degrees of freedom for treatments and error. With 4 treatment levels and 3 blocks, the degrees of freedom for treatments is 3, and for error is 6. Using an F-distribution table at α = 0.05, the critical F value is 4.76.

Data from a Randomized Block Design Are Shown in the Following