The concentration of HCl in a solution that is prepared by dissolving 5.5 g of HCl in 200 g of C₂H₆O is _ molal. A) 1.3 B) 0.75 C) 27.5 D) 7.5 × 10^-⁴ E) 3.3 × 10^-²

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Quizplus · Accepted Answer

To calculate the molality of the solution, we need to first calculate the moles of HCl present in the solution. Moles of HCl = Mass of HCl / Molar mass of HCl Molar mass of HCl = 1.0079 + 35.453 = 36.4609 g/mol Moles of HCl = 5.5 g / 36.4609 g/mol = 0.151 mol Now we need to calculate the mass of the solvent C₂H₆O. Mass of C₂H₆O = 200 g Now we can calculate the molality of the solution using the following formula: Molality = Moles of solute / Mass of solvent in kg Mass of solvent in kg = 200 g / 1000 = 0.2 kg Molality = 0.151 mol / 0.2 kg = 0.755 mol/kg ≈ 0.75 molal Therefore, the concentration of HCl in the solution that is prepared by dissolving 5.5 g of HCl in 200 g of C₂H₆O is 0.75 molal, which corresponds to choice (B).

The Concentration of HCl in a Solution That Is Prepared