The osmotic pressure of a solution formed by dissolving 25.0 mg of aspirin (C₉H₈O₄) in 0.250 L of water at 25 °C is atm. A) 1.14 × 10^-³ B) 0.0136 C) 1.38 D) 13.6 E) 2.45

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Quizplus · Accepted Answer

The osmotic pressure (π) can be calculated using the formula π = iMRT. First, calculate the molarity (M) of the solution: M = (mass of solute / molar mass of solute) / volume of solution in liters. The molar mass of aspirin is 180.16 g/mol. M = (0.025 g / 180.16 g/mol) / 0.250 L = 5.55 × 10^-4 M. Assuming aspirin does not ionize (i = 1), use R = 0.0821 L·atm/mol·K and T = 298 K. π = (1)(5.55 × 10^-4 M)(0.0821 L·atm/mol·K)(298 K) = 0.0136 atm.

The Osmotic Pressure of a Solution Formed by Dissolving 25