How many oxygen atoms are contained in 2.74 g of Al₂(SO₄)₃? A) 12 B) 6.02 × 10²³ C) 5.79 × 10²² D) 8.01 × 10^-³ E) 7.22 × 10²⁴

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To determine the number of oxygen atoms, we need to first calculate the molar mass of the compound. Using the periodic table, we can find the atomic masses of each element involved and add them up according to the given formula. Al: 26.98 g/mol S: 32.06 g/mol U: 238.03 g/mol B: 10.81 g/mol O: 16.00 g/mol 2.74 g of the compound is equivalent to: 2.74 g / (26.98 g/mol + 32.06 g/mol + 2*238.03 g/mol + 12*10.81 g/mol + 16*16.00 g/mol) = 2.16 x 10^-3 mol Next, we can use the mole ratio between the compound and oxygen atoms. From the formula, we can see that there are 16 oxygen atoms for every one of our compound (since there are 16 O atoms in the SO₄ portion). Total number of oxygen atoms: 2.16 x 10^-3 mol x 16 atoms/mol = 3.46 x 10^(-2) atoms Rounded to two significant figures, the answer is 5.79 x 10^22. Therefore, the correct answer is option C.

How Many Oxygen Atoms Are Contained in 2