How many grams of CH₃OH must be added to water to prepare 150 mL of a solution that is 2.0 M CH₃OH? A) 4.3 B) 2.4 C) 9.6 × 10³ D) 4.3 × 10² E) 9.6

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Quizplus · Accepted Answer

To find the grams of CH₃OH needed, use the formula: moles = molarity × volume (in liters). For a 2.0 M solution in 0.150 L, moles = 2.0 × 0.150 = 0.3 moles. The molar mass of CH₃OH is 32.04 g/mol, so mass = moles × molar mass = 0.3 × 32.04 = 9.612 g, which rounds to 9.6 g.

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How Many Grams of CH₃OH Must Be Added to Water