When the electron in a hydrogen atom moves from n = 8 to n = 2 light with a wavelength of
Nm is emitted.
A) 657
B) 389
C) 487
D) 93.8
E) 411

Question

Quizplus · Accepted Answer

The energy of the emitted photon can be calculated using the equation E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. The energy difference between the initial and final energy levels of the electron can be calculated using the equation ΔE = -Rh(1/nf^2 - 1/ni^2), where Rh is the Rydberg constant, nf is the final energy level, and ni is the initial energy level. Setting these two equations equal to each other and solving for λ, we get λ = hc/ΔE = (hc*Rh*(1/nf^2 - 1/ni^2))^-1. Plugging in nf = 2, ni = 8, and the constants, we get λ = 389 nm. Therefore, the answer is B.

When the Electron in a Hydrogen Atom Moves from N