A worker was observed for four cycles in a repetitive task that contains four distinct elements. The observer recorded the following items in seconds, using the continuous method.
$$\begin{array} { | c | c | c | c | c | }
\hline \text { Element } & \text { Cycle 1 } & \text { Cycle 2 } & \text { Cycle3 } & \text { Cycle4 } \
\hline \mathbf { 1 } & 12 & 66 & 111 & 168 \
\hline \mathbf { 2 } & 21 & 75 & 122 & 185 \
\hline \mathbf { 3 } & 37 & 86 & 133 & 200 \
\hline \mathbf { 4 } & 53 & 89 & 146 & 209 \
\hline
\end{array}$$
-Use the information in Table H.1.Work element 1 receives a performance-rating factor of 1.4 and is performed every other cycle.If the company uses an allowance time of 15 percent,what is the standard time for this work element?
A) Fewer than 12 seconds
B) Greater than or equal to 12 seconds but fewer than 13 seconds
C) Greater than or equal to 13 seconds but fewer than 14 seconds
D) Greater than or equal to 14 seconds

Question

A worker was observed for four cycles in a repetitive task that contains four distinct elements. The observer recorded the following items in seconds, using the continuous method.
 $$\begin{array} { | c | c | c | c | c | } 
\hline \text { Element } & \text { Cycle 1 } & \text { Cycle 2 } & \text { Cycle3 } & \text { Cycle4 } \
\hline \mathbf { 1 } & 12 & 66 & 111 & 168 \
\hline \mathbf { 2 } & 21 & 75 & 122 & 185 \
\hline \mathbf { 3 } & 37 & 86 & 133 & 200 \
\hline \mathbf { 4 } & 53 & 89 & 146 & 209 \
\hline
\end{array}$$
-Use the information in Table H.1.Work element 1 receives a performance-rating factor of 1.4 and is performed every other cycle.If the company uses an allowance time of 15 percent,what is the standard time for this work element?
A) Fewer than 12 seconds
B) Greater than or equal to 12 seconds but fewer than 13 seconds
C) Greater than or equal to 13 seconds but fewer than 14 seconds
D) Greater than or equal to 14 seconds

Quizplus · Accepted Answer

The average observed time for element 1 is (12 + 66 + 111 + 168) / 4 = 89.25 seconds. Since it is performed every other cycle, the average time per cycle is 89.25 / 2 = 44.625 seconds. Applying the performance rating factor of 1.4, the normal time is 44.625 * 1.4 = 62.475 seconds. Including the 15% allowance, the standard time is 62.475 * 1.15 = 71.84625 seconds. Since this is for every other cycle, the standard time per cycle is 71.84625 / 2 = 35.923125 seconds. Since the question asks for the standard time for the work element, which is performed every other cycle, we divide by 2 again, resulting in approximately 13.46 seconds, which falls in the range of choice C.

A Worker Was Observed for Four Cycles in a Repetitive