Use a graphing utility to graph the equation.Use a standard setting.Approximate any intercepts.
Y = |x + 2|

A)Intercepts: (0, -2), (0, 2)
B)Intercepts: (-2, 0), (0, -2)
C)Intercepts: (2, 0), (0, 2)
D)Intercepts: (-2, 0), (0, 2)
E)Intercepts: (-2, 0), (2, 0)

Question

Use a graphing utility to graph the equation.Use a standard setting.Approximate any intercepts. ​
Y = |x + 2|
​
A)Intercepts: (0, -2), (0, 2) ​ 
B)​Intercepts: (-2, 0), (0, -2) ​ 
C)​Intercepts: (2, 0), (0, 2) ​ 
D)Intercepts: (-2, 0), (0, 2) ​ 
E)​Intercepts: (-2, 0), (2, 0) ​

Quizplus · Accepted Answer

The absolute value of x+2 is equal to x+2 when x+2 is positive (to the right of -2) and equal to -(x+2) when x+2 is negative (to the left of -2). Therefore, the graph will be a "V" shape with the vertex at (-2,0) and the intercepts at (-2,0) and (0,2). Choice D is the only one that includes these intercepts.

Use a Graphing Utility to Graph the Equation