Calculate the number of oxygen atoms in 1.187 g of nickel(II) carbonate. A) 1.807 × 10²⁶ B) 5.535 × 10²³ C) 6.022 × 10²¹ D) 1.282 × 10²² E) 1.807 × 10²²

Question

Quizplus · Accepted Answer

- The molar mass of Nickel (II) carbonate ((NiCO3)) is:

Ni: 58.69 g/mol
C: 12.01 g/mol
O: 16.00 g/mol (3 atoms per molecule)

Molar mass of NiCO3 = (58.69 g/mol) + (12.01 g/mol) + 3(16.00 g/mol) = 118.69 g/mol

- Number of moles of NiCO3 in 1.187 g:

n = mass/molar mass = 1.187 g / 118.69 g/mol = 0.01 moles

- Number of oxygen atoms:

There are three oxygen atoms per molecule of NiCO3, so we can find the total number of oxygen atoms by multiplying the number of molecules by 3:

Number of oxygen atoms = 0.01 moles x 3 atoms/molecule x Avogadro's number (6.022 x 10^23 atoms/mol)
= 1.807 x 10^22 atoms

Therefore, the correct answer is E) 1.807 × 10^22.

Calculate the Number of Oxygen Atoms in 1