Choose the ground state electron configuration for Zr²⁺. A)[Kr] 5s² B)[Kr] 5s²4d² C)[Kr] 4d² D)[Kr] E)[Kr] 5s²4d⁴

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Zirconium (Zr) has the electron configuration [Kr]4d²5s². Sulfur (S) has the electron configuration [Ne]3s²3p⁴. Phosphorus (P) has the electron configuration [Ne]3s²3p³. The superscript numbers indicate the number of electrons in the corresponding subshell. The electron configuration for Zr^{2+ would be obtained by removing one electron from the 5s orbital of zirconium and adding it to the 3p orbital of sulfur. The electron configuration for} would involve adding two electrons to the 3s orbital of sulfur and one electron to the 3p orbital. Putting these configurations together, we get [Kr]4d².

Choose the Ground State Electron Configuration for Zr2+

Choose the Ground State Electron Configuration for Zr²⁺