Identify the ground-state electron configuration for Rb⁺. A) [Ar]4s²4p⁶ B) [Kr]5s¹ C) [Ar]4s²3d¹⁰4p⁶ D) [Kr]5s² E) [Kr]5s²4d²

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The Rb⁺ ion is formed by the loss of one electron from the neutral rubidium atom, which has the configuration [Kr]5s¹. Removing one electron results in the configuration [Kr], which is equivalent to [Ar]4s²3d¹⁰4p⁶.

Identify the Ground-State Electron Configuration for Rb⁺