Place the following substances in order of decreasing vapour pressure at a given temperature. BeF₂ CH₃OH OF₂ A) CH₃OH OF₂ BeF₂ B) BeF₂ OF₂ CH₃OH C) OF₂ CH₃OH BeF₂ D) OF₂ BeF₂ CH₃OH E) BeF₂ CH₃OH OF₂

Question

Place the following substances in order of decreasing vapour pressure at a given temperature. BeF₂ CH₃OH OF₂ A) CH₃OH > OF₂> BeF₂ B) BeF₂ > OF₂> CH₃OH C) OF₂ > CH₃OH > BeF₂ D) OF₂ > BeF₂ > CH₃OH E) BeF₂ > CH₃OH > OF₂

Quizplus · Accepted Answer

OF₂ is a small, non-polar molecule with weak intermolecular forces, leading to a high vapor pressure. CH₃OH, being polar and capable of hydrogen bonding, has a lower vapor pressure than OF₂. BeF₂ is an ionic compound with strong ionic bonds, resulting in the lowest vapor pressure among the three.

Place the Following Substances in Order of Decreasing Vapour Pressure