Place the following solutions in order of increasing osmotic pressure. I. 0.15 mol L^-1 C₂H₆O₂ II. 0.15 mol L^-1 MgCl₂ III. 0.15 mol L^-1 NaCl A) III

Question

Place the following solutions in order of increasing osmotic pressure. I. 0.15 mol L^-1 C₂H₆O₂ II. 0.15 mol L^-1 MgCl₂ III. 0.15 mol L^-1 NaCl A) III < I < II B) II < III < I C) I < II < III D) II < I < III E) I < III < II

Quizplus · Accepted Answer

Osmotic pressure depends on the concentration of particles in solution. I (C2H6O2) is a non-electrolyte, so it contributes 0.15 mol L^-1 particles. III (NaCl) dissociates into 2 ions, contributing 0.30 mol L^-1 particles. II (MgCl2) dissociates into 3 ions, contributing 0.45 mol L^-1 particles. Thus, the order is I < III < II.

Place the Following Solutions in Order of Increasing Osmotic Pressure